24x^2+8x-64=0

Solution for 24x^2+8x-64=0 equation:

24x^2+8x-64=0

a = 24; b = 8; c = -64;
Δ = b2-4ac
Δ = 82-4·24·(-64)
Δ = 6208
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6208}=\sqrt{64*97}=\sqrt{64}*\sqrt{97}=8\sqrt{97}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8\sqrt{97}}{2*24}=\frac{-8-8\sqrt{97}}{48}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8\sqrt{97}}{2*24}=\frac{-8+8\sqrt{97}}{48}
$